81b^2+8=24

Solution for 81b^2+8=24 equation:

81b^2+8=24

We move all terms to the left:

81b^2+8-(24)=0

We add all the numbers together, and all the variables

81b^2-16=0

a = 81; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·81·(-16)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*81}=\frac{-72}{162}
=-4/9
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*81}=\frac{72}{162}
=4/9
$